“Sex
Linkage” – What does it mean?
Tom Barnhart, Lima, OH
In pigeons, the following characteristics are due to genes that are on the sex chromosome and therefore such characteristics can be used to determine the sex of youngsters as soon as they feather out: Ash red (symbol BA), brown (symbol b), almond (symbol St), faded (symbol StF), qualmond (symbol StQ), reduced (symbol r), dilute (symbol d), and pale (symbol dP). There are also a few others, but they are rather obscure and the average fancier need not concern himself with them. Capital letters indicate that a particular gene is dominant to normal (which we consider to be a common blue bar, and sometimes refer to as “wild type”), and the characteristic will be visible any time the bird possesses the gene for that characteristic on either or both sex chromosomes. Lower case letters mean the gene is recessive to normal and the corresponding characteristic will only be visible when that gene is present twice, that is, on both chromosomes.
-----1-------------2--------------------------------3-----4------
The relative proximity of the numbers indicates the relative spacing of these positions on the chromosome itself. All of the genes mentioned occur at one of these four locations. Locus 1 is called the ash-red locus, because it is here that the ash red and brown genes occur. Locus 2 is the almond locus, and here the almond, faded, and qualmond genes occur. Locus 3 is the reduced locus and locus 4 is the dilute locus, where dilute and pale genes occur. On a normal blue pigeon (any pattern – bar, check, or barless), there will be a “normal” or “wild-type” gene (symbol “+”) at each of these locations, and none of the other color genes will be present. The presence of any of the other color genes may or may not alter the appearance of the pigeon, depending on whether the gene is recessive or dominant to normal and whether the bird in question is a cock or a hen.
At locus 2, there will be one – and only one – of the following: normal (+), almond (St), faded (StF), or qualmond (StQ).
At locus 3 will be either normal (+) or reduced (r).
At locus 4 we will find exactly one of normal (+), dilute (d), or pale (dP).
As noted earlier, a normal blue pigeon will be have “+” at each locus.
A blue cock with no other mutant color genes will have a pair of chromosomes that can be diagrammed like this:
A blue hen will look like the above, but with only one chromosome: + + + + .
Her second chromosome is usually represented by a dot or nothing at all.
An ash red bar (“silver” in the parlance of Racing Homer breeders in the U. S.) or red check cock will have a chromosome diagram like this:
or like this:
Both will appear as ash red pigeons, but the first is “heterozygous” (one copy of the ash red gene) and the second is “homozygous” (2 copies). The first pigeon is ash red on one chromosome and blue on the other, but the pigeon appears ash red because the ash red gene is dominant to the blue. The only indication that the first pigeon is not homozygous is that he may show some small dark spots on the tail or primaries.
An almond, faded or qualmond cock, like an ash red, need have just one copy of the respective gene in order to show the effects, since those genes are dominant to normal.
Because reduced is a recessive gene, a reduced cock will be
Likewise, a dilute or pale cock must be homozygous because those genes are also recessive.
A dilute hen, of course, will be + + + d and a reduced hen will be + + r + .
Again, I emphasize that a hen cannot carry any hidden sex-linked factors, and this is because she has just the one active sex chromosome.
In a future article, we will look at some specific matings, what color of offspring can be expected, and how the breeder can judiciously choose his matings so that the youngsters can be sexed based on their color.